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2x^2+40000=6x^2
We move all terms to the left:
2x^2+40000-(6x^2)=0
We add all the numbers together, and all the variables
-4x^2+40000=0
a = -4; b = 0; c = +40000;
Δ = b2-4ac
Δ = 02-4·(-4)·40000
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{640000}=800$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-800}{2*-4}=\frac{-800}{-8} =+100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+800}{2*-4}=\frac{800}{-8} =-100 $
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